How do you differentiate $F(x)=3/4x^8$ ?

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Answer 1 · 2017-05-10T15:03:07

$F'(x) = 6x^7$

First, multiply the coefficient by the exponent:
$3/4$ $xx$ $8$ $=$ $24/4$ $=$ $6$

Next, lower the exponent by one:
$x^(8-1)$ $=$ $x^7$

Put the derivative together:
$6x^7$

How do you differentiate F(x)=3/4x^8F(x)=3/4x^8?