Question

How do you differentiate `g(x) = (6x+9)sin(6x)` using the product rule?

Answer 1

`g'(x)=18(2x+3)(cos6x)+6(sin6x)`

Explanation:

`g(x)=(6x+9)(sin6x)`

`g'(x)=(6x+9)times6(cos6x)+(sin6x)times6`

`g'(x)=18(2x+3)(cos6x)+6(sin6x)`