How do you differentiate y=5x^3(sinx)^2?
1 Answer
Aug 8, 2017
Explanation:
"differentiate using the "color(blue)"product rule"
"given "y=g(x).h(x)" then "
dy/dx=g(x)h'(x)+h(x)g'(x)larr" product rule"
g(x)=5x^3rArrg'(x)=15x^2
h(x)=(sinx)^2rArrh'(x)=2sinxcosx=sin2x
rArrdy/dx=5x^3sin2x+15x^2sin^2x