How do you differentiate $y=x^3(2x-5)^4$ ?

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Answer 1 · 2017-05-26T01:24:10

Using the product rule $(1 xx d2 + 2 xx d1)$ , you would set 1 as $x^3$ and 2 as $(2x-5)^4$ .

The derivative of 1 would be $3x^2$ and the derivative of 2 is $4(2x-5)^3 *2$ , or $8(2x-5)^3$ using the chain rule.

Now plug in the values into the product rule, so that $(x^3 xx 8(2x-5)^3) + ((2x-5)^4) xx 3x^2)$ .

This expanded is $112 x^6 - 960 x^5 + 3000 x^4 - 4000 x^3 + 1875 x^2$ .

How do you differentiate y=x^3(2x-5)^4y=x^3(2x-5)^4?