How do you divide $\frac{- 2 i + 2}{- 7 i + 8}$ $( -2i +2) / (- 7 i + 8 )$ in trigonometric form?

Question

How do you divide $\frac{- 2 i + 2}{- 7 i + 8}$ $( -2i +2) / (- 7 i + 8 )$ in trigonometric form?

1 Answer

Impact of this question

1376 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-15T14:43:06

You don't. These are perfectly easy to divide in standard rectangular form and the denominator is difficult to express exactly in trigonometric form. So

$\frac{2 - 2 i}{8 - 7 i} \times \frac{8 + 7 i}{8 + 7 i} = \frac{(16 + 14) + i (- 16 + 14)}{64 + 49} = \frac{30}{113} - \frac{2}{113} i$ ${ 2 -2i}/(8 - 7i} times {8+7i}/{8+7i} = {(16+14)+i( -16 + 14)}/{64 +49} = 30/113 - 2/113i$

Science

Math

Humanities

... and beyond

How do you divide $\frac{- 2 i + 2}{- 7 i + 8}$ $( -2i +2) / (- 7 i + 8 )$ in trigonometric form?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you divide ( -2i +2) / (- 7 i + 8 )−2i+2−7i+8( -2i +2) / (- 7 i + 8 ) in trigonometric form?

1 Answer

Related questions

Impact of this question

How do you divide $\frac{- 2 i + 2}{- 7 i + 8}$ $( -2i +2) / (- 7 i + 8 )$ in trigonometric form?