How do you divide $(2 x^{2} + 4 x - 4) \div (x - 2)$ $(2x^2+4x-4)div(x-2)$ using synthetic division?

Question

How do you divide $(2 x^{2} + 4 x - 4) \div (x - 2)$ $(2x^2+4x-4)div(x-2)$ using synthetic division?

1 Answer

Impact of this question

2161 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-27T15:25:13

The answer is $\frac{2 x^{2} + 4 x - 4}{x - 2} = 2 x + 8 + \frac{12}{x - 2}$ $(2x^2+4x-4)/(x-2)=2x+8+12/(x-2)$

Explanation:

Let's do the long division
$2 x^{2} + 4 x - 4$ $2x^2+4x-4$ $a a a a a$ $color(white)(aaaaa)$ $∣$ $∣$ $x - 2$ $x-2$
$2 x^{2} - 4 x$ $2x^2-4x$ $a a a a a a a a a$ $color(white)(aaaaaaaaa)$ $∣$ $∣$ $2 x + 8$ $2x+8$
$a a$ $color(white)(aa)$ $0 + 8 x - 4$ $0+8x-4$
$a a$ $color(white)(aa)$ $0 + 8 x - 16$ $0+8x-16$
$a a a a a a$ $color(white)(aaaaaa)$ $0 + 12$ $0+12$

So $\frac{2 x^{2} + 4 x - 4}{x - 2} = 2 x + 8 + \frac{12}{x - 2}$ $(2x^2+4x-4)/(x-2)=2x+8+12/(x-2)$

The remainder can be obtained
let $f (x) = 2 x^{2} + 4 x - 4$ $f(x)=2x^2+4x-4$
then $f (2) = 2 \cdot 2^{2} + 4 \cdot 2 - 4 = 12$ $f(2)=2*2^2+4*2-4=12$

Science

Math

Humanities

... and beyond

How do you divide $(2 x^{2} + 4 x - 4) \div (x - 2)$ $(2x^2+4x-4)div(x-2)$ using synthetic division?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you divide (2x^2+4x-4)div(x-2)(2x2+4x−4)÷(x−2)(2x^2+4x-4)div(x-2) using synthetic division?

1 Answer

Explanation:

Related questions

Impact of this question

How do you divide $(2 x^{2} + 4 x - 4) \div (x - 2)$ $(2x^2+4x-4)div(x-2)$ using synthetic division?