Question

How do you divide `2x^2+5x–12÷2x^2 – 7x + 6`?

Answer 1

I tried factoring the numerator and denominator toget:
`2x^2+5x-12=(x+4)(2x-3)`
`2x^2-7x+6=(2x-3)(x-2)`
So you get:
`(2x^2+5x-12)/(2x^2-7x+6)=[(x+4)(2x-3)]/[(2x-3)(x-2)]=`
Simplifying:
`=(x+4)/(x-2)`