How do you divide $(2x^3-7x^2-17x-3)div(2x+3)$ using long division?

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Answer 1 · 2017-01-12T08:11:05

The remainder is $=0$ and the quotient is $=x^2-5x-1$

Let's go for a long division

$color(white)(aaaa)$ $2x^3-7x^2-17x-3$ $color(white)(aaaa)$ $∣$ $color(blue)(2x+3)$

$color(white)(aaaa)$ $2x^3+3x^2$ $color(white)(aaaaaaaaaaaaa)$ $∣$ $color(red)(x^2-5x-1)$

$color(white)(aaaaa)$ $0-10x^2-17x$

$color(white)(aaaaaaa)$ $-10x^2-15x$

$color(white)(aaaaaaaaaaa)$ $0-2x-3$

$color(white)(aaaaaaaaaaaaa)$ $-2x-3$

$color(white)(aaaaaaaaaaaaaa)$ $-0-0$

The remainder is $=0$ and the quotient is $=x^2-5x-1$

$(2x^3-7x^2-17x-3)/(2x+3)=x^2-5x-1$

How do you divide (2x^3-7x^2-17x-3)div(2x+3)(2x^3-7x^2-17x-3)div(2x+3) using long division?