How do you divide $(2x^4+7)div(x^2-1)$ using long division?

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Answer 1 · 2016-12-15T17:18:41

The remainder is $=9$ and the quotient is $=2x^2+2$

Let's do the long division

$color(white)(aaaa)$ $2x^4$ $color(white)(aaaa)$ $color(white)(aaaa)$ $+7$ $∣$ $x^2-1$

$color(white)(aaaa)$ $2x^4-2x^2$ $color(white)(aaaa)$ $color(white)(a)$ #∣2x^2+2#

$color(white)(aaaaa)$ $0+2x^2+7$ $color(white)(aaaa)$

$color(white)(aaaaaaa)$ $+2x^2-2$ $color(white)(aaaa)$

$color(white)(aaaaaaaaa)$ $+0+9$ $color(white)(aaaa)$

The remainder is $=9$ and the quotient is $=2x^2+2$

$(2x^4+7)/(x^2-1)=2x^2+2+9/(x^2-1)$

How do you divide (2x^4+7)div(x^2-1)(2x^4+7)div(x^2-1) using long division?