How do you divide $(3x)/(2-2x)div(4x)/(1-x)$ ?

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Answer 1 · 2018-04-05T18:30:51

$3/8$

$(3x)/(2-2x)-:(4x)/(1-x)$

$:.=(3x)/(2-2x)xx(1-x)/(4x)$

$:.=(3x)/(2(cancel(1-x)))xxcancel(1-x)/(4x)$

$:.=(3cancelx)/(8cancelx)$

$:.=3/8$

How do you divide (3x)/(2-2x)div(4x)/(1-x)(3x)/(2-2x)div(4x)/(1-x)?