How do you divide −3x3+6x2−13x−5x+1?
1 Answer
Feb 21, 2018
Explanation:
one way is to use the divisor as a factor in the numerator
consider the numerator
−3x2(x+1)+3x2+6x2−13x−5
=−3x2(x+1)+9x(x+1)−9x−13x−5
=−3x2(x+1)+9x(x+1)−22(x+1)+22−5
=−3x2(x+1)+9x(x+1)−22(x+1)+17
quotient =−3x2+9x−22, remainder =17
⇒−3x3+6x2−13x−5x+1
=−3x2+9x−22+17x+1
