How do you divide $(4x^3 - 2x^2 + x - 7) ÷ (x - 8)$ ?

Question

1785 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-07-01T22:00:42

$(4x^3 -2x^2 +x -7)/(x-8) = 4x^2 +30x +241 + 1921/(x-8)$

You use the process of long division.

enter image source here

So,

$(4x^3 -2x^2 +x -7)/(x-8) = 4x^2 +30x +241 + 1921/(x-8)$

Check:

$(x-8)(4x^2 +30x +241 + 1921/(x-8))= (x-8)(4x^2+30x+241) +1921$

$= 4x^3 + 30x^2 + 241x -32x^2 – 240x -1928 +1921 = 4x^3 -2x^2 +x -7$

How do you divide (4x^3 - 2x^2 + x - 7) ÷ (x - 8) (4x^3 - 2x^2 + x - 7) ÷ (x - 8) ?