How do you divide $(5-12i)/(6+2i)$ in trigonometric form?

Question

1432 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-02T15:01:09

$3/20-(41i)/20$

Multiply the expression with the cojugate of 6+2i, both in the numerator and the denominator. Thus it is,

$(5-12i)/ (6+2i) * (6-2i)/(6-2i)$ = $(6-82i)/40$ = $3/20-(41i)/20$

How do you divide (5-12i)/(6+2i) (5-12i)/(6+2i) in trigonometric form?