How do you divide $(5x^4+14x^3+9x)div(x^2+3x)$ using long division?

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Answer 1 · 2016-11-14T15:16:20

The quotient is $=5x^2-x+3$

Let's do the long division

$color(white)(aaaa)$ $5x^4+14x^3+9x$ $color(white)(aaaa)$ $∣$ $x^2+3x$

$color(white)(aaaa)$ $5x^4+15x^3$ $color(white)(aaaaaaaaa)$ $∣$ $5x^2-x+3$

$color(white)(aaaaaa)$ $0-x^3$

$color(white)(aaaaaaaa)$ $-x^3-3x^2$

$color(white)(aaaaaaaaaa)$ $0+3x^2+9x$

$color(white)(aaaaaaaaaaaa)$ $+3x^2+9x$

$color(white)(aaaaaaaaaaaaaaaa)$ $0+0$

$(5x^4+14x^3+9x)/(x^2+3x)=5x^2-x+3$

The quotient is $=5x^2-x+3$

How do you divide (5x^4+14x^3+9x)div(x^2+3x)(5x^4+14x^3+9x)div(x^2+3x) using long division?