How do you divide $(7-9i)/(6+i)$ in trigonometric form?

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Answer 1 · 2018-05-03T20:53:56

$= 33/37-61/37i$

$(7-9i)/(6+i) | *(6-i)$

$((7-9i)(6-i))/((6+i)(6-i))$

$(42-61i+9i^2)/(36-6i+6i-i^2)$

$(42-61i+9i^2)/(36-i^2)$

$(42-9-61i)/(36+1)$

$(33-61i)/(37)$

$= 33/37-61/37i$

How do you divide (7-9i)/(6+i) (7-9i)/(6+i) in trigonometric form?