How do you divide $\frac{7 i - 5}{2 i + 1}$ $( 7i-5) / (2i+1)$ in trigonometric form?

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How do you divide $\frac{7 i - 5}{2 i + 1}$ $( 7i-5) / (2i+1)$ in trigonometric form?

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Answer 1 · 2016-04-24T11:07:45

In trigonometric form $- 3.85 (cos 242.1 + i sin 242.1)$ $-3.85(cos242.1+i sin 242.1)$

Explanation:

$\frac{7 i - 5}{2 i + 1} = \frac{(7 i - 5) (2 i - 1)}{(2 i + 1) (2 i - 1)} = \frac{- 14 + 5 - 17 i}{- 4 - 1} = - \frac{1}{5} \cdot (- 9 - 17 i)$ $(7i-5)/(2i+1) = ((7i-5)(2i-1))/((2i+1)(2i-1)) = (-14+5-17i)/(-4-1)= -1/5*(-9-17i)$
$r = \sqrt{9^{2} + 17^{2}} = 19.24$ $r=sqrt(9^2+17^2)=19.24$ $θ = 180 + {tan}^{- 1} (\frac{17}{9}) = {242.1}^{0}$ $theta= 180+tan^-1(17/9)=242.1^0$ As it is on 3rd quadrant 180 has been added.
In trigonometric form : $- \frac{19.24}{5} (cos 242.1 + i sin 242.1)$ $-19.24/5(cos242.1+i sin 242.1)$
or $- 3.85 (cos 242.1 + i sin 242.1)$ $-3.85(cos242.1+i sin 242.1)$ [Ans]

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How do you divide $\frac{7 i - 5}{2 i + 1}$ $( 7i-5) / (2i+1)$ in trigonometric form?

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Explanation:

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How do you divide $\frac{7 i - 5}{2 i + 1}$ $( 7i-5) / (2i+1)$ in trigonometric form?