How do you divide $(8x10^5)/(2x10^-2)$ ?

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Answer 1 · 2015-03-28T15:03:37

Separate the coefficients and the exponents and process them separately (then re-combine)

$(8xx10^5)/(2xx10^-2)$
can be written as $8/2 xx (10^5)/(10^-2)$

$8/2 = 4$

$10^5/10^(-2) = 10^5*10^2 = 10^7$

Recombining
$(8xx10^5)/(2xx10^-2) = 4 xx 10^7$

How do you divide (8x10^5)/(2x10^-2)(8x10^5)/(2x10^-2)?