How do you divide $\frac { ( m - 2) ^ { 2} } { n ^ { 2} } \div \frac { 8m - 16} { 4n }$ ?

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Answer 1 · 2017-02-18T04:39:01

$(m-2)/(2n)$

Remember, you can change a division problem to a multiplication problem when you reciprocate the second term:

$((m-2)^2)/n^2 -: (8m-16)/(4n) = ((m-2)^2)/n^2 * (4n)/(8m-16)$

Factor the second terms denominator: $((m-2)^2)/n^2 * (4n)/(8(m-2))$

Rearrange & Simplify: $(4n)/(8n^2) * (m-2)^2/(m-2) = (m-2)/(2n)$

How do you divide \frac { ( m - 2) ^ { 2} } { n ^ { 2} } \div \frac { 8m - 16} { 4n }\frac { ( m - 2) ^ { 2} } { n ^ { 2} } \div \frac { 8m - 16} { 4n }?