How do you divide ( i-1) / (i -2 )i−1i−2 in trigonometric form?

1 Answer
Yonas Yohannes
Apr 10, 2016

C = (3-i)/3 = 1-i/3C=3−i3=1−i3

Explanation:

Given: C= C_n/C_d=( -1+i)/(-2 +i )C=CnCd=−1+i−2+i
Required: The resultant to C_n/C_dCnCd
Solution Strategy: Multiply both nominator and denominator by complex conjugate of the denominator, C_d= -2+iCd=−2+i.
Complex conjugate of C_d^"*" =(-2 -i)C*d=(−2−i)
Thus:
C = (C_n@C_d^"*")/(C_d@C_d^"*")=[( -1+i)@(-2 -i)]/[(-2+i )@(-2 -i)]C=Cn∘C*dCd∘C*d=(−1+i)∘(−2−i)(−2+i)∘(−2−i)
C = (3-i)/3 = 1-i/3C=3−i3=1−i3

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