How do you divide $(x^2+3)div(x+3)$ using synthetic division?

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Answer 1 · 2017-09-10T18:11:50

$(x^2+3)/(x+3) = x -3+12/(x+3)$

$(x^2+3)/(x+3) = (x^2+3x-3x-9+12)/(x+3) = (x(x+3))/(x+3) + (-3(x+3))/(x+3) +12/(x+3)= x -3+(12)/(x+3)$

How do you divide (x^2+3)div(x+3)(x^2+3)div(x+3) using synthetic division?