How do you divide $(x^2-7x+12)/(x-5)$ ?

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Answer 1 · 2015-06-29T18:53:59

$(x^2-7x+12)/(x-5) = x – 2 + 2/(x-5)$

You use the process of long division.

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So,

$(x^2-7x+12)/(x-5) = x – 2 + 2/(x-5)$

Check:

$(x-5)(x-2+2/(x-5)) = (x-5)(x-2) + 2 = x^2 -7x +10 + 2 = x^2 -7x +12$

How do you divide (x^2-7x+12)/(x-5)(x^2-7x+12)/(x-5)?