How do you divide (x ^ { 2} - 9x + 25) \div ( x - 5)(x2−9x+25)÷(x−5)?
1 Answer
Sep 13, 2017
Explanation:
"one way is to use the divisor as a factor in the numerator"one way is to use the divisor as a factor in the numerator
"consider the numerator"consider the numerator
color(red)(x)(x-5)color(magenta)(+5x)-9x+25x(x−5)+5x−9x+25
=color(red)(x)(x-5)color(red)(-4)(x-5)color(magenta)(-20)+25=x(x−5)−4(x−5)−20+25
=color(red)(x)(x-5)color(red)(-4)(x-5)+5=x(x−5)−4(x−5)+5
"quotient "=color(red)(x-4)," remainder "=5quotient =x−4, remainder =5
rArr(x^2-9x+25)/(x-5)=x-4+5/(x-5)⇒x2−9x+25x−5=x−4+5x−5
