How do you divide x3−13x−18x−4?

1 Answer
Jim G.
Aug 8, 2017

x2+4x+3−6x−4

Explanation:

one way is to use the divisor as a factor in the numerator

consider the numerator

x2(x−4)+4x2−13x−18

=x2(x−4)+4x(x−4)+16x−13x−18

=x2(x−4)+4x(x−4)+3(x−4)+12−18

=x2(x−4)+4x(x−4)+3(x−4)−6

quotient =x2+4x+3, remainder =−6

⇒x3−13x−18x−4=x2+4x+3−6x−4

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