How do you divide $(x^3-2x-6) / (x-3)$ ?

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Answer 1 · 2016-07-17T17:27:34

$x^2 +3x +7$ rem 15

Using synthetic division:
$(x^3 + 0x^2 - 2x -6) div (x-3)$

Use the coefficients.

$" | 1 0 -2 -6"$
$" 3 | 3 9 21"$

$" 1 3 7 15"$

"Multiply the 3 by each number at the bottom"

The answers are the coefficients from $x^2, x^1, x^0, and R$

$(x^3 + 0x^2 - 2x -6) div (x-3)$

= $1x^2 +3x +7$ rem 15

How do you divide (x^3-2x-6) / (x-3)(x^3-2x-6) / (x-3)?