How do you divide $( x^3+4x^2+x-6 )/(x-3)$ ?

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Answer 1 · 2015-12-16T03:15:34

$((x^2+1)(x+4)(x-6))/(x-3)$

Assuming that you mean simplifying:

$(x^3+4x^2+x-6)/(x-3)$

$=(x^2(x+4)+1(x-6))/(x-3)$

$=((x^2+1)(x+4)(x-6))/(x-3)$ , $x!=3$

How do you divide ( x^3+4x^2+x-6 )/(x-3)( x^3+4x^2+x-6 )/(x-3)?