How do you divide $(x^3+5x^2-2)div(x+4)$ using long division?

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Answer 1 · 2016-08-11T02:45:59

I found: $(x^2+x-4)$ and $14$ as remainder.

Have a look:
enter image source here

I introduced the $0x$ into the original to simplify the operation.

How do you divide (x^3+5x^2-2)div(x+4)(x^3+5x^2-2)div(x+4) using long division?