How do you divide $x^3 + 6x^2 + 12x + 8$ by $x +2$ ?

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Answer 1 · 2016-07-09T20:58:29

$(x^3+6x^2+12+8)/(x+2) = x^2+4x+4$

One way is to long divide the coefficients like this:

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The process is similar to long division of numbers.

In this particular example, we find the quotient $1, 4, 4$ meaning $x^2+4x+4$ , with no remainder. That is:

$(x^3+6x^2+12+8)/(x+2) = x^2+4x+4$

How do you divide x^3 + 6x^2 + 12x + 8x^3 + 6x^2 + 12x + 8 by x +2x +2?