How do you divide x^3+6x^2-2x+3x3+6x2−2x+3 by x-3? Algebra Rational Equations and Functions Division of Polynomials 1 Answer Tony B Jun 27, 2017 x^2+9x+25+78/(x-3)x2+9x+25+78x−3 Explanation: " "x^3+6x^2-2x+3 x3+6x2−2x+3 color(magenta)(x^2)(x-3) ->ul(x^3-3x^2larr" Subtract") " "0+9x^2-2x+3 color(magenta)(9x)(x-3)->" "ul(9x^2-27xlarr" Subtract") " "0+25x+3 color(magenta)(25)(x-3)->" "ul(25x-75larr" Subtract") " "color(magenta)(0+78 larr" Remainder") color(magenta)( x^2+9x+25+78/(x-3)) Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide 9x^2-16 by 3x+4? How do you divide \frac{x^2+2x-5}{x}? How do you divide \frac{x^2+3x+6}{x+1}? How do you divide \frac{x^4-2x}{8x+24}? How do you divide: (4x^2-10x-24) divide by (2x+3)? How do you divide: 5a^2+6a-9 into 25a^4? How do you simplify (3m^22 + 27 mn - 12)/(3m)? How do you simplify (25-a^2) / (a^2 +a -30)? See all questions in Division of Polynomials Impact of this question 1508 views around the world You can reuse this answer Creative Commons License