How do you divide $\frac{- x^{4} - 4 x^{3} + 2 x^{2} - 7 x - 7}{x - 2}$ $(-x^4-4x^3+2x^2-7x-7)/(x-2)$ ?

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Answer 1 · 2018-02-24T18:56:53

$- x^{3} - 6 x^{2} - 10 x - 27$ $-x^3-6x^2-10x-27$ with a remainder of $- 61$ $-61$

Using long division,

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How do you divide (-x^4-4x^3+2x^2-7x-7)/(x-2) −x4−4x3+2x2−7x−7x−2(-x^4-4x^3+2x^2-7x-7)/(x-2) ?