Question

How do you divide `(y^4+9y^2+20)/(y^2+4)`?

Answer 1

`y^2+5`

Explanation:

We can simplify this by replacing `y^2` with `x`

`(y^4+9y^2+20)/(y^2+4) = (x^2+9x+20)/(x+4)`

which has a (perhaps) more apparent factoring of the numerator:
`color(white)("XXXX")` `((x+5)cancel((x+4)))/(cancel((x+4))`

Then restoring `x` with `y^2`
`rArr (y^2+5)`