How do you draw the graph of $y = 2 - sin x$ $y=2-sinx$ for $0 \leq x < 2 π$ $0<=x<2pi$ ?

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How do you draw the graph of $y = 2 - sin x$ $y=2-sinx$ for $0 \leq x < 2 π$ $0<=x<2pi$ ?

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Answer 1 · 2017-12-03T09:29:55

See below.

Explanation:

If we look at $y = 2 - sin x$ $color(blue)(y=2-sinx)$ in relation to $y = sin x$ $color(blue)(y=sinx)$ , we can see that, if we reflect $y = sin x$ $color(blue)(y=sinx)$ in the x axis, we get $y = - sin x$ $color(blue)(y=-sinx)$ . If we then translate this 2 units in the positive y direction we get $y = 2 - sin x$ $color(blue)(y=2-sinx)$ .

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How do you draw the graph of $y = 2 - sin x$ $y=2-sinx$ for $0 \leq x < 2 π$ $0<=x<2pi$ ?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How do you draw the graph of y=2−sinxy=2-sinx for 0≤x<2π0<=x<2pi?

1 Answer

Explanation:

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Impact of this question

How do you draw the graph of $y = 2 - sin x$ $y=2-sinx$ for $0 \leq x < 2 π$ $0<=x<2pi$ ?