How do you draw the Lewis Structure for $O P B r_{3}$ $OPBr_3$ ?

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How do you draw the Lewis Structure for $O P B r_{3}$ $OPBr_3$ ?

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Answer 1 · 2016-06-30T15:06:28

$Of phosphoryl bromide?$ $"Of phosphoryl bromide?"$ . There are $6 + 5 + 3 \times 7 = 32$ $6+5+3xx7=32$ electrons to distribute.

Explanation:

Lewis structures of $O = P B r_{3}$ $O=PBr_3$ or $^{-} O -^{+} P B r_{3}$ $""^(-)O-^(+)PBr_3$ are appropriate. The 2nd one is probably more common now. Each structure distributes 16 pairs of valence electrons as is required.

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How do you draw the Lewis Structure for $O P B r_{3}$ $OPBr_3$ ?

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How do you draw the Lewis Structure for $O P B r_{3}$ $OPBr_3$ ?