How do you evaluate $(2.9 \times 10^{- 2}) (5.2 \times 10^{- 9})$ $(2.9times10^-2)(5.2times10^-9)$ ?

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How do you evaluate $(2.9 \times 10^{- 2}) (5.2 \times 10^{- 9})$ $(2.9times10^-2)(5.2times10^-9)$ ?

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Answer 1 · 2017-08-02T00:39:15

The 'normal' parts are multiplied and the exponents are added.
$1.5 \times 10^{- 10}$ $1.5 xx10^(−10)$

Explanation:

Remember that exponents are just a way to simplify writing very large and very small numbers. They do not change the way the numbers combine in mathematics. The rules for combination do have to be observed.

$(2.9 \times 10^{- 2}) \times (5.2 \times 10^{- 9})$ $(2.9 × 10^(−2))xx(5.2 × 10^(−9))$

$(2.9 \times 5.2) \times (10^{- 2} \times 10^{- 9})$ $(2.9 × 5.2) xx(10^(−2) × 10^(−9))$

$(15.08) \times (10^{- 11})$ $(15.08) xx(10^(−11))$

$1.5 \times 10^{- 10}$ $1.5 xx10^(−10)$

The "longhand" version would be a simple multiplication:

$0.029 \times 0.0000000052 = 0.00000000015$ $0.029 xx 0.0000000052 = 0.00000000015$

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How do you evaluate $(2.9 \times 10^{- 2}) (5.2 \times 10^{- 9})$ $(2.9times10^-2)(5.2times10^-9)$ ?

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Explanation:

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How do you evaluate (2.9×10−2)(5.2×10−9)(2.9times10^-2)(5.2times10^-9)?

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How do you evaluate $(2.9 \times 10^{- 2}) (5.2 \times 10^{- 9})$ $(2.9times10^-2)(5.2times10^-9)$ ?