How do you evaluate $2(a-b)^2-5c$ given a=12, b=9, c=4?

Question

3026 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-02T14:53:38

The answer is $-2$

$2(color(red)a-color(blue)b)^2-5color(violet)c color(white)(aaa)$ given $a=color(red)(12), b=color(blue)9, c=color(violet) 4$

Substitute $color(red)(12)$ for $color(red)a$ , $color(blue)9$ for $color(blue)b$ , and $color(violet)4$ for $color(violet)c$ .

$2(color(red)(12)-color(blue)9)^2-5(color(violet)4)$

$2(color(white)(aa)3color(white)(aaa))^2-20$

$2(9)-20$

$18-20$

$-2$

How do you evaluate 2(a-b)^2-5c2(a-b)^2-5c given a=12, b=9, c=4?