How do you evaluate $2 cos (pi/3) - 6 tan (pi/3)$ ?

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Answer 1 · 2018-06-15T08:46:19

$color(purple)(=> 1 - 6sqrt3)$

![https://www.tes.com/teaching-resource/table-of-exact-values-of-trigonometric-functions-6437384](useruploads.socratic.org)

$"From table above", cos (pi/3) = 1/2, tan (pi/3) = sqrt3$

$2 cos (pi/3) - 6 tan (pi/3) = 2*(1/2) - 6 * (sqrt3)$

$color(purple)(=> 1 - 6sqrt3)$

How do you evaluate 2 cos (pi/3) - 6 tan (pi/3) 2 cos (pi/3) - 6 tan (pi/3)?