How do you evaluate $2 {(n)}^{2} + 1$ $2(n)^2 + 1$ if n = 5?

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Answer 1 · 2015-12-21T00:10:07

Substitute $5$ $5$ for $n$ $n$ and evaluate the expression using the order of operations to find

$2 n^{2} + 1 = 51$ $2n^2+1 = 51$ for $n = 5$ $n=5$

Plugging in $5$ $5$ for $n$ $n$ and following the order of operations (exponents before multiplication before addition):

$2 {(5)}^{2} + 1 = 2 (25) + 1$ $2(5)^2 + 1 = 2(25)+1$

$= 50 + 1$ $= 50+1$

$= 51$ $= 51$

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