How do you evaluate $\frac{2 c^{3} - a b}{4}$ $(2c^3-ab)/4$ given a=12, b=9, c=4?

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How do you evaluate $\frac{2 c^{3} - a b}{4}$ $(2c^3-ab)/4$ given a=12, b=9, c=4?

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Answer 1 · 2017-06-30T12:06:50

See a solution process below:

Explanation:

To evaluate this expression substitute:

$12$ $color(red)(12)$ for $a$ $color(red)(a)$

$9$ $color(blue)(9)$ for $b$ $color(blue)(b)$

$4$ $color(green)(4)$ for $c$ $color(green)(c)$

$\frac{2 c^{3} - a b}{4}$ $(2color(green)(c)^3 - color(red)(a)color(blue)(b))/4$ becomes:

$\frac{(2 \times 4^{3}) - (12 \times 9)}{4} \Rightarrow$ $((2 xx color(green)(4)^3) - (color(red)(12) xx color(blue)(9)))/4 =>$

$\frac{(2 \times 64) - 108}{4} \Rightarrow$ $((2 xx color(green)(64)) - 108)/4 =>$

$\frac{128 - 108}{4} \Rightarrow$ $(128 - 108)/4 =>$

$\frac{20}{4} \Rightarrow$ $20/4 =>$

$5$ $5$

Answer 2 · 2017-06-30T12:46:00

$5$ $5$

Explanation:

$substitute the given values into the expression$ $"substitute the given values into the expression"$

$= \frac{(2 \times 4^{3}) - (12 \times 9)}{4}$ $=((2xx4^3)-(12xx9))/4$

$= \frac{128 - 108}{4}$ $=(128-108)/4$

$= \frac{20}{4}$ $=20/4$

$= 5$ $=5$

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How do you evaluate $\frac{2 c^{3} - a b}{4}$ $(2c^3-ab)/4$ given a=12, b=9, c=4?

2 Answers

Explanation:

Explanation:

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