How do you evaluate #3( a + c/a) -b # given a= 2, b= 7, and c= 4?

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Answer 1 · 2016-08-02T08:29:54

If #a=2#, #b=7# and #c=4#, #3(a+c/a)-b=5#

As #a=2#, #b=7# and #c=4#,

#3(a+c/a)-b#

#hArr3(2+4/2)-7#

= #3(2+2)-7#

= #3xx4-7#

= #12-7=5#