How do you evaluate $3 (a + \frac{c}{a}) - b$ $3( a + c/a) -b$ given a= 2, b= 7, and c= 4?

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Answer 1 · 2016-08-02T08:29:54

If $a = 2$ $a=2$ , $b = 7$ $b=7$ and $c = 4$ $c=4$ , $3 (a + \frac{c}{a}) - b = 5$ $3(a+c/a)-b=5$

As $a = 2$ $a=2$ , $b = 7$ $b=7$ and $c = 4$ $c=4$ ,

$3 (a + \frac{c}{a}) - b$ $3(a+c/a)-b$

$\Leftrightarrow 3 (2 + \frac{4}{2}) - 7$ $hArr3(2+4/2)-7$

= $3 (2 + 2) - 7$ $3(2+2)-7$

= $3 \times 4 - 7$ $3xx4-7$

= $12 - 7 = 5$ $12-7=5$

How do you evaluate 3( a + c/a) -b 3(a+ca)−b3( a + c/a) -b given a= 2, b= 7, and c= 4?