How do you evaluate $3^{ln 0.2}$ $3^ln0.2$ ?

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Answer 1 · 2017-02-24T17:34:56

$3^{ln 0.2} = 0.171$ $3^(ln0.2)=0.171$

Let $3^{ln 0.2} = x$ $3^(ln0.2)=x$ . Taking natural log on both sides, we get

$ln 0.2 ln 3 = ln x$ $ln0.2ln3=lnx$ and hence

$x = e^{ln 0.2 ln 3}$ $x=e^(ln0.2ln3)$

= $e^{- 1.609 \times 1.0986}$ $e^(-1.609xx1.0986)$

= $e^{- 1.76815} = 0.171$ $e^(-1.76815)=0.171$

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