How do you evaluate ${(5 - w)}^{2} + x$ $(5-w)^2+x$ if w=6, x=0.4, y=1/2, z=-3?

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How do you evaluate ${(5 - w)}^{2} + x$ $(5-w)^2+x$ if w=6, x=0.4, y=1/2, z=-3?

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Answer 1 · 2017-06-09T18:58:41

$1.4$ $1.4$

Explanation:

$substitute the given values into the expression$ $"substitute the given values into the expression"$

$\Rightarrow {(5 - 6)}^{2} + 0.4$ $rArr(5color(red)(-6))^2+color(magenta)(0.4)$

$= {(- 1)}^{2} + 0.4$ $=(-1)^2+0.4$

$= 1 + 0.4$ $=1+0.4$

$= 1.4$ $=1.4$

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How do you evaluate ${(5 - w)}^{2} + x$ $(5-w)^2+x$ if w=6, x=0.4, y=1/2, z=-3?

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How do you evaluate ${(5 - w)}^{2} + x$ $(5-w)^2+x$ if w=6, x=0.4, y=1/2, z=-3?