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How do you evaluate $- 6 log 100$ $-6log100$ ?

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Konstantinos Michailidis · MeneerNask

Oct 26, 2015

It is

$- 6 log 100 = - 6 {log 10}^{2} = - 12$ $-6log100=-6log10^2=-12$ because ${log 10}^{2} = 2$ $log10^2=2$

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