How do you evaluate 7√2 + √50 - 2/18?

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Answer 1 · 2018-03-21T02:52:39

$7 \sqrt{2} + \sqrt{50} - \frac{2}{18} = 12 \sqrt{2} - \frac{1}{9}$ $7sqrt2+sqrt50-2/18=color(blue)(12sqrt2-1/9$

Simplify:

$7 \sqrt{2} + \sqrt{50} - \frac{2}{18}$ $7sqrt2+sqrt50-2/18$

Simplify $\frac{2}{18}$ $2/18$ to $\frac{1}{9}$ $1/9$ .

$7 \sqrt{2} + \sqrt{50} - \frac{1}{9}$ $7sqrt2 + sqrt50-1/9$

Prime factorize $\sqrt{50}$ $sqrt50$ .

$7 \sqrt{2} + \sqrt{2 \times 5^{5}} - \frac{1}{9}$ $7sqrt2+sqrt(2xx5^5)-1/9$

Apply rule: $\sqrt{a^{2}} = a$ $sqrt(a^2)=a$

$7 \sqrt{2} + 5 \sqrt{2} - \frac{1}{9}$ $7sqrt2+5sqrt2-1/9$

Simplify.

$12 \sqrt{2} - \frac{1}{9}$ $12sqrt2-1/9$