How do you evaluate $(a^2div4b)+c$ given a=12, b=9, c=4?

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Answer 1 · 2017-04-14T13:14:57

$8$

$a^2-:4b+c=a^2/(4b)+c$

$"Substitute the given values into the expression"$

$rArr(12)^2/(4xx9)+4$

$=144/36+4$

$=4+4$

$=8$

How do you evaluate (a^2div4b)+c(a^2div4b)+c given a=12, b=9, c=4?