How do you evaluate a(b^x)a(bx) given a=-2, b=3, x=1?

1 Answer
Sep 29, 2017

See a solution process below:

Explanation:

Substitute:

  • color(red)(-2)2 for color(red)(a)a
  • color(blue)(3)3 for color(blue)(b)#
  • color(green)(1)1 for color(green)(x)x

color(red)(a)(color(blue)(b)^color(green)(x))a(bx) becomes:

color(red)(-2) xx (color(blue)(3)^color(green)(1)) => color(red)(-2) xx 3 => -62×(31)2×36