How do you evaluate $A r c cos (\frac{4}{5})$ $Arc cos (4/5)$ ?

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How do you evaluate $A r c cos (\frac{4}{5})$ $Arc cos (4/5)$ ?

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Answer 1 · 2017-06-12T16:25:59

$x = 36^{\circ} 87 + k 360^{\circ}$ $x = 36^@87 + k360^@$

Explanation:

$cos x = \frac{4}{5}$ $cos x = 4/5$ --> find arc x
Calculator gives:
cos x = 0.8 --> arc $x = 36^{\circ} 87$ $x = 36^@87$
Unit circle gives another arc $x = - 36^{\circ} 87$ $x = - 36^@87$ that has the same cos value.
Extended answers:
$x = \pm 36^{\circ} 87 + k 360^{\circ}$ $x = +- 36^@87 + k360^@$

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How do you evaluate $A r c cos (\frac{4}{5})$ $Arc cos (4/5)$ ?

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