How do you evaluate $arccos(1/(2*sqrt(2)))$ ?

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Answer 1 · 2017-03-25T17:50:38

$arc cos(1/(2sqrt2))=69.3^@$

Let $arc cos(1/(2sqrt2))=A$

then $cosA=1/(2sqrt2)=sqrt2/4=0.35355$

and using tables or scientific calculator

$A=69.3^@$

Answer 2 · 2017-03-25T22:21:21

$x = +- 69^@30 + k360^2$

$cos x = 1/(2sqrt2) = sqrt2/4 = 0.3535$
Calculator and unit circle give -->
$x = +- 69^@30 + k360^@$

How do you evaluate arccos(1/(2*sqrt(2)))arccos(1/(2*sqrt(2)))?