How do you evaluate $c + {(2 a)}^{2}$ $c + (2a)^2$ given a = 3 and c = −1?

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How do you evaluate $c + {(2 a)}^{2}$ $c + (2a)^2$ given a = 3 and c = −1?

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Answer 1 · 2017-02-16T12:48:53

See the entire solution process below:

Explanation:

To evaluate this expression for the given values we must substitute $3$ $color(red)(3)$ for $a$ $color(red)(a)$ and substitute $- 1$ $color(blue)(-1)$ for $c$ $color(blue)(c)$ in the expression and then calculate the result:

$c + {(2 a)}^{2}$ $color(blue)(c) + (2color(red)(a))^2$ becomes:

$- 1 + {(2 \times 3)}^{2} \to - 1 + {(6)}^{2} \to - 1 + 36 \to 35$ $color(blue)(-1) + (2 xx color(red)(3))^2 -> color(blue)(-1) + (6)^2 -> color(blue)(-1) + 36 -> 35$

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How do you evaluate $c + {(2 a)}^{2}$ $c + (2a)^2$ given a = 3 and c = −1?

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How do you evaluate $c + {(2 a)}^{2}$ $c + (2a)^2$ given a = 3 and c = −1?