Question

How do you evaluate `c + (2a)^2` given a = 3 and c = −1?

Answer 1

See the entire solution process below:

Explanation:

To evaluate this expression for the given values we must substitute `color(red)(3)` for `color(red)(a)` and substitute `color(blue)(-1)` for `color(blue)(c)` in the expression and then calculate the result:

`color(blue)(c) + (2color(red)(a))^2` becomes:

`color(blue)(-1) + (2 xx color(red)(3))^2 -> color(blue)(-1) + (6)^2 -> color(blue)(-1) + 36 -> 35`