Question

How do you evaluate `cos^-1(1)`?

Answer 1

`2npi, n=0.+-1,+-2,+-3...`

Explanation:

The principal values of `cos^(-1)(1) in [0,2pi]` are 0 and `2pi`

So, the general value = .`2npi, n=0.+-1,+-2,+-3..`