How do you evaluate ${cos}^{- 1} [tan (\frac{π}{3})]$ $cos^-1[tan(pi/3)]$ ?

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Answer 1 · 2016-07-10T07:43:38

Invalid inverse cosine.

The cosine of ${cos}^{- 1} (tan (\frac{π}{3})) = tan (\frac{π}{3}) = \sqrt{3} > 1 .$ $cos^(-1)(tan (pi/3))=tan (pi/3) =sqrt 3 > 1.$

A cosine cannot exceed 1.

How do you evaluate cos^-1[tan(pi/3)]cos−1[tan(π3)]cos^-1[tan(pi/3)]?