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How do you evaluate $cos (\frac{17 π}{6})$ $cos((17pi)/6)$ ?

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Apr 15, 2016

$cos (\frac{17 π}{6}) = cos (3 π - \frac{π}{6}) = - cos (\frac{π}{6}) = - \frac{\sqrt{3}}{2}$ $cos((17pi)/6)=cos(3pi-pi/6)=-cos(pi/6)=-sqrt3/2$

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